Integrand size = 20, antiderivative size = 53 \[ \int \csc (a+b x) \sqrt {\sin (2 a+2 b x)} \, dx=-\frac {\arcsin (\cos (a+b x)-\sin (a+b x))}{b}+\frac {\log \left (\cos (a+b x)+\sin (a+b x)+\sqrt {\sin (2 a+2 b x)}\right )}{b} \]
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Time = 0.07 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.100, Rules used = {4393, 4390} \[ \int \csc (a+b x) \sqrt {\sin (2 a+2 b x)} \, dx=\frac {\log \left (\sin (a+b x)+\sqrt {\sin (2 a+2 b x)}+\cos (a+b x)\right )}{b}-\frac {\arcsin (\cos (a+b x)-\sin (a+b x))}{b} \]
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Rule 4390
Rule 4393
Rubi steps \begin{align*} \text {integral}& = 2 \int \frac {\cos (a+b x)}{\sqrt {\sin (2 a+2 b x)}} \, dx \\ & = -\frac {\arcsin (\cos (a+b x)-\sin (a+b x))}{b}+\frac {\log \left (\cos (a+b x)+\sin (a+b x)+\sqrt {\sin (2 a+2 b x)}\right )}{b} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.98 \[ \int \csc (a+b x) \sqrt {\sin (2 a+2 b x)} \, dx=-\frac {\arcsin (\cos (a+b x)-\sin (a+b x))}{b}+\frac {\log \left (\cos (a+b x)+\sin (a+b x)+\sqrt {\sin (2 (a+b x))}\right )}{b} \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 2.64 (sec) , antiderivative size = 157, normalized size of antiderivative = 2.96
method | result | size |
default | \(\frac {2 \sqrt {-\frac {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )}{\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}-1}}\, \left (\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}-1\right ) \sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}\, \sqrt {-2 \tan \left (\frac {a}{2}+\frac {x b}{2}\right )+2}\, \sqrt {-\tan \left (\frac {a}{2}+\frac {x b}{2}\right )}\, \operatorname {EllipticF}\left (\sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )+1}, \frac {\sqrt {2}}{2}\right )}{b \sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right ) \left (\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{2}-1\right )}\, \sqrt {\tan \left (\frac {a}{2}+\frac {x b}{2}\right )^{3}-\tan \left (\frac {a}{2}+\frac {x b}{2}\right )}}\) | \(157\) |
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Leaf count of result is larger than twice the leaf count of optimal. 242 vs. \(2 (51) = 102\).
Time = 0.27 (sec) , antiderivative size = 242, normalized size of antiderivative = 4.57 \[ \int \csc (a+b x) \sqrt {\sin (2 a+2 b x)} \, dx=\frac {2 \, \arctan \left (-\frac {\sqrt {2} \sqrt {\cos \left (b x + a\right ) \sin \left (b x + a\right )} {\left (\cos \left (b x + a\right ) - \sin \left (b x + a\right )\right )} + \cos \left (b x + a\right ) \sin \left (b x + a\right )}{\cos \left (b x + a\right )^{2} + 2 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) - 1}\right ) - 2 \, \arctan \left (-\frac {2 \, \sqrt {2} \sqrt {\cos \left (b x + a\right ) \sin \left (b x + a\right )} - \cos \left (b x + a\right ) - \sin \left (b x + a\right )}{\cos \left (b x + a\right ) - \sin \left (b x + a\right )}\right ) - \log \left (-32 \, \cos \left (b x + a\right )^{4} + 4 \, \sqrt {2} {\left (4 \, \cos \left (b x + a\right )^{3} - {\left (4 \, \cos \left (b x + a\right )^{2} + 1\right )} \sin \left (b x + a\right ) - 5 \, \cos \left (b x + a\right )\right )} \sqrt {\cos \left (b x + a\right ) \sin \left (b x + a\right )} + 32 \, \cos \left (b x + a\right )^{2} + 16 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) + 1\right )}{4 \, b} \]
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Timed out. \[ \int \csc (a+b x) \sqrt {\sin (2 a+2 b x)} \, dx=\text {Timed out} \]
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\[ \int \csc (a+b x) \sqrt {\sin (2 a+2 b x)} \, dx=\int { \csc \left (b x + a\right ) \sqrt {\sin \left (2 \, b x + 2 \, a\right )} \,d x } \]
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\[ \int \csc (a+b x) \sqrt {\sin (2 a+2 b x)} \, dx=\int { \csc \left (b x + a\right ) \sqrt {\sin \left (2 \, b x + 2 \, a\right )} \,d x } \]
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Timed out. \[ \int \csc (a+b x) \sqrt {\sin (2 a+2 b x)} \, dx=\int \frac {\sqrt {\sin \left (2\,a+2\,b\,x\right )}}{\sin \left (a+b\,x\right )} \,d x \]
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